Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
11x-7
2x + 7 + 5x - 4 - x = (2x + 5x - x) + (7 - 4) = 6x + 3
When working on equations such as this, try to isolate the unknown (or variable) on one side of the equation with all other terms being on the opposite side. If the coefficient of the unknown is not 1 then multiply or divide so that it is brought to 1. 5x - 4 = -6x + 3 : add 4 to both sides 5x = -6x + 7 : add 6x to both sides 11x = 7 : divide both sides by 11 x = 7/11
6x + 4 just add like terms, (5x can be multiplyed by 4 but NOT added because 4 doesn't have an x) 5x + x or 5x+1x=6x and you would have positive 4 left over or +4 so the answer would be 6x+4 ps. that was along answer for something so simple, hope I didn't end up confusing you more :/
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
11x-7
2x + 7 + 5x - 4 - x = (2x + 5x - x) + (7 - 4) = 6x + 3
5x + 4 = 6x - 2Add 2 to each side of the equation:5x + 6 = 6xSubtract 5x from each side:6 = x
2(3x + 4) + 5x - 2
When working on equations such as this, try to isolate the unknown (or variable) on one side of the equation with all other terms being on the opposite side. If the coefficient of the unknown is not 1 then multiply or divide so that it is brought to 1. 5x - 4 = -6x + 3 : add 4 to both sides 5x = -6x + 7 : add 6x to both sides 11x = 7 : divide both sides by 11 x = 7/11
6x + 4 just add like terms, (5x can be multiplyed by 4 but NOT added because 4 doesn't have an x) 5x + x or 5x+1x=6x and you would have positive 4 left over or +4 so the answer would be 6x+4 ps. that was along answer for something so simple, hope I didn't end up confusing you more :/
6x+3=27 6x=24 (subtract 3 from each side) x=4 (divide both sides by 6)
-4
(4x^4 −5x^3 +6x+11)−?=x^4 −x^3 −x^2 −3x+2
9194 It may not be right but this is what i come up with
4