2(3x + 4) + 5x - 2
2x+x+5+3x-6=6x-1
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
9x - 3(x + 13y) = 9x - 3x - 39y = 6x - 39y = 3(2x - 13y)
6x - 12 = 3x + 12 Add twelve to both sides.6x - 12 + 12 = 3x + 12 + 12Simplify.6x = 3x + 24Subtract 3x from both sides.6x - 3x = 3x + 24 - 3xSimplify.3x = 24Divide both sides by 3.x = 8The answer is x = 8.
No. 3x plus 2x = 5x. 3x multiplied by 2x = 6x²
(-3x+1)(-2x+1)
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
5x+3x-6x+4x+2x-x+10 This expression can be simplified to: 7x+10 (7 being the coefficient of x)
6x^2 + 5x + 1 = (3x +1) (2x + 1)
5x + x - 6x + 2x = 2x
6x2+5x+1 = (3x+1)(2x+1) when factored
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
3x+5x-2x = 24 6x = 24 x = 4
In an algebraic expression, terms are the elements separated by the plus or minus signs. On simplifying further we get: 8 - 5x and it has two terms: 8 & -5x. But, without simplifying we have four terms which are 3x, 8, -2x & -6x.
6x2-5x-21 = (3x-7)(2x+3)
6x - 2x + 5x - 3First you want to have the x's by theirselves and the numbers by themselvesIt will still be:6x - 2x + 5x - 3Here, you do 6x - 2x.4x + 5x -3Then you combine 4x + 5x.9x - 3Simplified just like that