6,4,2 0
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The difference between the successive numbers is 4. so the next three numbers could be 4, 0 and -4.
Assuming the sequence of numbers declines by 5 each time, the next three numbers would be 40, 35 and 30.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.
The pattern is multiply by -1, add 5, repeat. The next three numbers are: -7, -2, 2