12, 13, 16 Add three, then add 1, then add three, then add 1, and so on so forth
12, 10 and 15 the are alternatively increased by 2 and 3
11, -10, 9
-3 0 3 then 6 9 12 15 18 21 and so on ...
11, 12, and 13
-17, -22
-12, 14, -16
12, 13, 16 Add three, then add 1, then add three, then add 1, and so on so forth
12, 10 and 15 the are alternatively increased by 2 and 3
Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.
The next two numbers are 26 & 78.
The next three numbers are: 87, 141, 228. Each number in the sequence after the first two is the sum of the previous two numbers. This is a variation of the Fibonacci sequence which starts with 1, 1, ... (and then continues ..., 2, 3, 5, 8, 13, ...).
There are infinitely many possible patterns. One possibility is: t(n) = (-4x5 + 65x4 - 370x3 + 1015x2 - 1246x + 600)/60 IF that is the case, then the next three numbers are 59, 22 and -131.
12
11, -10, 9
21 and 13. The pattern is t(n) = (-n4 + 10n3 - 23n2 + 38n - 12)/12
-3 0 3 then 6 9 12 15 18 21 and so on ...