(1) Take the difference of the two previous numbers in sequence (2) Add 4 to this difference. (3) Take the number from step #2 and add it to the previous number in the sequence. For example, to find the next number in the sequence: (1) 121 - 90 = 31 (2) 31 + 4 = 35 (3) 121 + 35 = 156
121
22
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
121 divided by 3 equals 40 with a remainder of 1.
0.525
121
22
21
121/40
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
The number is 55+66 = 121
121 divided by 3 equals 40 with a remainder of 1.
0.525
The sequence represents a non-convergence sequence. The sequences carries out -27, 17, 19, -21, 44, 2, -40,-42,-42. This is a math sequencing solution that gives a pattern to the original numbers given.
42 + 79 = 121 (40+70) + (2+9) = = 110 + 11 = 121
21/40
61