6(p + 3) = 6p + 18
3(p + 6) or 3p + 18
3(p - 6) 3p - 18
The expression that represents two times the sum of p and 8 is 2(p + 8).
It is: 4*(q+p)
Pretty confusing :P -3*2*1 = -6 Hope this helps
3(p + 6) or 3p + 18
3(p - 6) 3p - 18
The expression that represents two times the sum of p and 8 is 2(p + 8).
It is: 4*(q+p)
Pretty confusing :P -3*2*1 = -6 Hope this helps
'3' H3PO3 To calculate oxidation no. First sepatate out the ion. In this case PO3^(3-). Using oxygen as tha standard at '-2'. Then the oxygen moiety is '3 X -2 = -6' Creating a little sum P + -6 = -3 (The charge on the ion) . Add '6' t NB 'P' is in the same group as 'N' . Elements in this Group have variable oxid'n numbers. Hence P -6 + 6 = -3 +6 P = +3 The oxidation number of 'P'.
P(1or2)=2/6=1/3 P(4<=x<=6)=2/3 when rolled 15 times (2/3)^15=.0023
2(p+11)
7p + 3
p2 + 9p + 18/ p + 6(p + 6)(p + 3)/ p + 6(p + 6)(p + 3)/ p + 6p + 3
P(not even) = P(odd) = 3/6=1/3 When rolled 6 times, the probability of an even number not showing up is (1/3)^6 = 1/729.
100 : P