6(p + 3) = 6p + 18
3(p - 6) 3p - 18
Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.
The expression that represents two times the sum of p and 8 is 2(p + 8).
It is: 4*(q+p)
6(p + 3) = 6p + 18
3(p - 6) 3p - 18
Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.
The expression that represents two times the sum of p and 8 is 2(p + 8).
It is: 4*(q+p)
2(p+11)
100 : P
1/2(9+p)=p-3
" 5(p+r) " is.
the sum of p and r is p + r5 times this sum is 5 × (p + r) = 5(p + r)Multiplication is not written as it looks like an 'x' - it is implied by two things next to each other.The brackets are needed as the addition needs to be done before the multiplication.
As an expression it is: 5(p+r) which means 5p+5r
Let A = rolling a double Let B = sum is 11 P(A)=6/36=1/6 P(B)=2/36=1/18 since (5,6) and (6,5) produce a sum of 11. We want to find P(A/B)= P(A & B) / P(B) = 0 / P(B)=0 P(A & B) represent the event getting a double and the sum being 11.