(11, 5)
a = 11 and b = 5.
10x^3 plus 14x^2-4x+16
x = 11 y = 16
11+16=8+ d. In this problem, you should move all numbers to one side. Like this: 11+16-8=d. Now combine, and you get the answer, which is: d=19.
6x-14x+16=27+11 answer: 4
(11, 5)
There must be some operators between 16 and 10 and also between 10x and 14x, please clarify
a = 11 and b = 5.
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. The new question submitted is 16 + 10x = 14x -4 Transposing and collecting terms we have 10x - 14x = -4 -16 -4x = -20 x = 5
10x^3 plus 14x^2-4x+16
11-4y=-5 -4y=-16 y=4
2+14=16
x = 11 y = 16
96
11+16=8+ d. In this problem, you should move all numbers to one side. Like this: 11+16-8=d. Now combine, and you get the answer, which is: d=19.
It is 112