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Q: -4y plus 11 equals -5

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8x plus 4y equals 5 is 8x + 4y = 5.

5x - 4y = -41 => 5x = 4y - 41 => x = (4y - 41)/5 Then 4x + 35 = 4*[(4y - 41)/5] + 35 = 16y/5 - 164/5 + 35 = 16y/5 -11/5 or (16y - 11)/5

x = 5, y = -1

6.75

4y + 4 = 3y - 5 y = -9

6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2

(-1, 5)

(-1, 5)

(8 + 4) x 5...

5

5x + 4y = 204y = -5x + 20y = (-5/4)x + 5

x - 2 = 2 → x = 4 → x² - 4y² = 5 → 4² - 4y² = 5 → 4y² = 16 - 5 → 4y² = 11 → y² = 11/4 → y = ± √(11/4) → The points of intersection of x - 2 = 2 with x² - 4y² = 5 are (4, -√(11/4)) ≈ 4, -1.658) and (4, √(11/4)) ≈ 4, 1.658)

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