When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
There are 2 significant figures in 7.8x109^?
In both cases, there are 2 significant figures.
Two. When multiplying or dividing the answer is rounded to the fewest significant figures in the given measurements. 0.55 has only two significant figures, so the answer can have only two significant figures.
75.6 times 12.33 = 932.148 correct to 6 significant figures
4.884 has four significant figures and 2.25 has three significant figures. 4.884 x 2.25 = 10.989 = 11.0 rounded to three significant figures. When multiplying or dividing, the result must have the same number of significant figures as the number in the problem with the fewest significant figures.
It has 5 significant figures - one trailing zero is significant.
When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
The number 1.84 x 103 has three significant figures, 1.84. The 103 part of the number does not count when determining significant figures.
Four significant figures in 3.895.
6.5211 x 104 = 678.1944 678.1944 has 7 significant figures
5 significant figures Each figure that contributes to the accuracy of a value is considered significant. So 2.9979 has 5 significant figures. The 10^8 does not contribute to the accuracy as it simply indicates the number of trailing zeroes (i.e. 299,790,000) that are simply a result of rounding from the actual value (299,792,458)
The significant figures for 0.054 are 2. In a decimal number, leading zeros are not considered significant. Therefore, the significant figures in 0.054 are the digits 5 and 4. The zeros after the decimal point are considered significant.
There are 2 significant figures in 7.8x109^?
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
(4.73*1000*0.568)+1.61 = 2688.25 meaning that it has 6 significant figures
In both cases, there are 2 significant figures.