x=(-9/7) 7x+12=3 7x=(-9) x=(-9/7)
x = -1/3
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7
11x+9=7x+21 11x-7x=4 4x+9=21 21-9=12 4x=12 12 divided by 4= 3 x=3
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2
79
x=(-9/7) 7x+12=3 7x=(-9) x=(-9/7)
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
x = -1/3
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7
11x+9=7x+21 11x-7x=4 4x+9=21 21-9=12 4x=12 12 divided by 4= 3 x=3
7x - 2 = 4x + 9 3x - 2 = 9 3x = 11 x = 11/3
7x - 3 = 6 + x 7x - x = 6 + 3 6x = 9 x = 9/6 = 3/2 = 1 and 1/2 or 1.5
7x+3=10x-9(shift +3 & 10x) 7x-10x=-9-3(signs changed) -3x=-12(divide both sides by -3) x=4
7x + y + z = 6 7x + y + 4z = 9 y + x = 6 Take the first two statements and subtract them. 7x + y + z = 6 7x + y + 4z = 9 _____________ 0 + 0 - 3z = -3 Therefore: z = 1 Then you are left with: 7x + y + 1 = 6 7x + y + 4 = 9 which is impossible, so this is an impossible equation.