The goal is to solve for a value of x such that the equation is true. The equation is:
8x + 5 = 7x + 8
First, subtract 5 from both sides, so that there is only a constant on the right side.
8x = 7x + 3
Next, subtract 7x from both sides, so that the variable, x, is only on the left side.
x = 3
The result is x = 3.
8x plus 4y equals 5 is 8x + 4y = 5.
8x + 23 + 4x - 7x = 64; Find X To make this easier, add like terms: (8x + 4x - 7x) + 26 = 64 Use the order of operations: (12x - 7x) + 26 = 64 5x + 26 = 64 -26 -26 5x = 38 5 5 Finally: x = 7(3/5)
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
The answer is nine. Seriously. Here is my work if you don't believe me: 68=8x+23+4x-7x 68=8x-7x+23+4x 68=x+23+4x 68=x+4x+23 68=5x+23 68-23=5x 45=5x x=45/5 x=9
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
8x plus 4y equals 5 is 8x + 4y = 5.
8x + 23 + 4x - 7x = 64; Find X To make this easier, add like terms: (8x + 4x - 7x) + 26 = 64 Use the order of operations: (12x - 7x) + 26 = 64 5x + 26 = 64 -26 -26 5x = 38 5 5 Finally: x = 7(3/5)
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
The answer is nine. Seriously. Here is my work if you don't believe me: 68=8x+23+4x-7x 68=8x-7x+23+4x 68=x+23+4x 68=x+4x+23 68=5x+23 68-23=5x 45=5x x=45/5 x=9
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
(1, 1)
7x = 5+5x 7x-5x = 5 2x = 5 x = 2.5
7x is still the slope, no matter what x equals.
5
4x+5=7x-8 the ansewr is 3.25
23 = 7x + 7x - 5 = 14x - 5 14x = 23 + 5 = 28 x = 28/14 = 2
4x - 7 = 5 + 7x x = -4