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The goal is to solve for a value of x such that the equation is true. The equation is:
8x + 5 = 7x + 8
First, subtract 5 from both sides, so that there is only a constant on the right side.
8x = 7x + 3
Next, subtract 7x from both sides, so that the variable, x, is only on the left side.
x = 3
The result is x = 3.
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How do you write 8x plus 4y equals 5?
8x plus 4y equals 5 is 8x + 4y = 5.
8x plus 23 plus 4x - 7x equals 68 show work?
8x + 23 + 4x - 7x = 64; Find X To make this easier, add like terms: (8x + 4x - 7x) + 26 = 64 Use the order of operations: (12x - 7x) + 26 = 64 5x + 26 = 64 -26 -26 5x = 38 5 5 Finally: x = 7(3/5)
If AD equals 3x plus 5 AB equals 7x-3 and BC equals 8x-10 what is the value of x?
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
8x plus 23 plus 4x - 7x equals 68?
The answer is nine. Seriously. Here is my work if you don't believe me: 68=8x+23+4x-7x 68=8x-7x+23+4x 68=x+23+4x 68=x+4x+23 68=5x+23 68-23=5x 45=5x x=45/5 x=9
What is the answer to -7x plus 5 equals -9?
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
