8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
-8x + 4y = 28 Add 8x to each side: 4y = 8x + 28 Divide both sides by 4: y = 2x + 7
x=4, y=9 (4,9)
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
This can't be solved. You have two varibles.
8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
-8x + 4y = 28 Add 8x to each side: 4y = 8x + 28 Divide both sides by 4: y = 2x + 7
76
x=4, y=9 (4,9)
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
This can't be solved. You have two varibles.
4y - 8x + 12 = 0 4y = 8x - 12 y = 2x - 3 So the slope = 2 y-intercept = -3
4y-8x+12 = 0 4y = 8x-12 y = 2x-3 The slope is 2 and the y intercept is -3
(8 + 4) x 5...
x = -2 and y = 0
Multiply the first by 8 and the second by 3
It is not possible to solve a single linear equation in two unknown variables.