a b c, t r w, z p t; any three variables
P = 2L + 2W P/2 = L + W 28/2 = 8 + W 14 = 8 + W 6 = W A = LW A = (8)(6) A = 48 unit2
it has three cases 1st E1- two balls are whiteE2- three balls are whiteE4-four balls are whiteE4/w= (p(E3)*4C2/4C2)/(P(E1)*2C2/4C2+P(E2)3C2/4C2+P(E3)*4C2/4C2)WHERE-P(E1)=P(E2)=P(E3)=1/3----------------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white
the odds theoretically are almost infinity to 1 as they could be any color. -------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white
A b c d g j k l o p q r s t u v w x y.
h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = H k Q 7 _ o W q K p c
W. P. C. Davies was born in 1928.
Is the letter C
C. W. P. Moffatt has written: 'Science German course'
a b c, t r w, z p t; any three variables
W. B. C. has written: 'The infidel' -- subject(s): Apologetics, Free thought
Eevee learns the following moves: - Tail Whip - Tackle - Helping Hand - Sand Attack (D/P/Pt/HG/SS/B/W: Lvl 8) - Growl (D/P/Pt/HG/SS/B/W: Lvl 15) - Quick Attack (D/P/Pt/HG/SS/B/W: Lvl 22) - Bite (D/P/Pt/HG/SS/B/W: Lvl 29) - Baton Pass (D/P/Pt/HG/SS/B/W: Lvl 36) - Take Down (D/P/Pt/HG/SS/B/W: Lvl 43) - Last Resort (D/P/Pt/HG/SS/B/W: Lvl 50) - Trump Card (D/P/Pt/HG/SS/B/W: Lvl 57) TMs: 6,10,11,17,18,21,27,28,30,32,42,44,45,48,48,67,83,87,90 Pt/HG/SS Move tutors: Snore, Swift, Mud-Slap HG/SS Move tutors: Heal Bell, Headbutt
W=wrought p=pipe b=bend
It's been a while, but I'll take a stab at this one. Assuming this is a rectangular shape: width = w length = w + 12 perimeter = length + length + width + width As stated above, p = 7w, so: 7w (perimeter) = (w + 12) + (w + 12) + w + w 7w = 4w + 24 (simplifying the above) -4w -4w (getting all the w's on one side) ------------------ 3w = 24 w = 8 Checking our work. Substituting 8 for w: p = 7(8) p = 56 P = (8+12) + (8 + 12) + 8 + 8 p = 20 + 20 + 8 + 8 p = 56
P = 2L + 2W P/2 = L + W 28/2 = 8 + W 14 = 8 + W 6 = W A = LW A = (8)(6) A = 48 unit2
W=wrought p=pipe b=bend
2 W on a B P stands for "2 wheels on a bicycle pump," which is a common riddle or puzzle.