W=FD (W)ork=(F)orce*(D)istance
w x h
W/c .4/5
First define your variables and set up some equations. w= width of the rectangle. h= height. d= the diagonal. Our goal is to first solve for h and w so we can calculate perimeter. According to Pythagorean theorem, w^2 + h^2 = d^2 (we can do this because half of a rectangle is a right triangle). h^2 + w^2 = 17.55^2. Also, the length times width equals area (l x w=area). So, h x w =109.35 cm. Since you have 2 unknown variables and 2 equations, you can solve for the variables one at a time by using substitution. By manipulating the 2nd equation to isolate h, h= 109.35/w. Then, plug in your "h value" you just solved for into the 1st equation to get (109.35/w)^2 + w^2 = (17.55)^2. Simplifies to (11957.422/w^2) + w^2 = 308.0025. Manipulate and solve.
start real length L and width w calculate the area A= Lw calculate the circumference C=2(L+w) Display A and C End
You can calculate amperage (A) using the formula A = W / V, where W is the power in watts and V is the voltage. Simply divide the power in watts by the voltage to find the amperage.
I think you want to ask What does Barbiers Theorem says about a figure of constant width. Such a nice theorem establishes that if you have a compact figure C in the plane, that is closed and bounded, and C has constant width w, then the perimeter of C is "pi times w"
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. Mathematically, the equation can be written as W = ΔKE, where W is the work done on the object and ΔKE is the change in its kinetic energy.
There is no single formula for the width of any arbitrary shape. If however, you already have two points that define that width, then you can calculate the distance between them with simple Pythagorean theorem: w = [Δx2 + Δy2 + Δz2]1/2
W=FD (W)ork=(F)orce*(D)istance
To calculate win-lose, add the wins and the losses and divide the sum into the wins to calculate percentage of wins or divide into the losses to calculate the percentage of losses: W + L = Total; W ÷ Total = W%; L ÷ Total = L%: example: 12 W + 8 L = 20; 12W ÷ 20 = .60 or 60% wins; 8L ÷ 20 = .40 or 40% losses
Power can be calculated using the formula: Power (P) = Work (W) / Time (t). It is the rate at which work is done or the amount of energy transferred per unit time. The SI unit of power is the watt (W).
Suppose the width is W and the diagonal is D.Then, by Pythagoras's theorem, the length, L, is given by L = sqrt(D^2 - W^2).And then, area = L*W.
W. McCune has written: 'Automated deduction in equational logic and cubic curves' -- subject(s): Algebraic Curves, Automatic theorem proving, Curves, Algebraic
w x h
The formula you are looking for is R = W/I x I.
The heat rejected can be calculated using the first law of thermodynamics equation: Q = W - ΔU, where Q is the heat, W is the work, and ΔU is the change in internal energy. If the process is isothermal (constant temperature), then ΔU is zero, and heat rejected equals work done.