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How would you turn 8x-5y equals -40 into slop intercept?
To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
Find x 5 and 8 and x?
8x+40
What is the answer to 8x-40 equals 2x plus 2?
7. 8x-40=2x+2 4x-20=1x+1 3x-21=0 3x=21 therefore x=7
How do you find the value of x in -2-8 x 40?
Let me assume that this equation is -2 -8x = 40 It's usually best to move all the purely numerical items to one side first. Let me move the -2. Then, to do this I add 2 to both sides. -2 - 8x +2 = -8x = 40 + 2 = 42 or -8x = 42 Now, to yield x 'by itself' let me divide both sides by -8. (-8x)/-8 = x = 42/(-8) = -21/4 or x = -21/4
Is -4(-3x-8)-4x 8 equal to -8x 40?
4
8x plus 8 equals 40 what is x?
8x + 8=40 8x=40-8 8x=32 x=32/8 x=4
How would you turn 8x-5y equals -40 into slop intercept?
To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
How would you solve the equation x² plus 8x-40 equals 0?
x2 - 8x - 40 = 0 ∴ x2 - 8x = 40 ∴ x2 - 8x + 16 = 56 ∴ (x - 4)2 = 56 ∴ x - 4 = ± 561/2 ∴ x = 4 ± 561/2 ∴ x = 4 ± 2 × 141/2 ∴ x ≈ {11.4833, -3.4833}
Evaluate the expression 8x-40 when x is 30?
8(30) - 40 = 240 - 40 = 200.
40-8x when x 2?
If x = 2 then 40-(8*2) = 24
Find x 5 and 8 and x?
8x+40
What are the solutions to the equation below (4x plus 36)(8x-40)0?
Assuming you mean:(4x+36)(8x-40) = 0 then you can use the property that a product can only be zero if one of its factors is zero. In other words, you can change this to: 4x + 36 = 0 OR 8x - 40 = 0 Solve each of the individual solutions; their solutions are also solutions to the original equation.
What is the answer to 8x-40 equals 2x plus 2?
7. 8x-40=2x+2 4x-20=1x+1 3x-21=0 3x=21 therefore x=7
How do you work out negative 7 plus 8x plus forty plus ninety?
Since there is only an expression - not an equation - you can simplify it but there is nothing to work out or solve. -7 + 8x + 40 + 90 = 8x + 123
How do you find the value of x in -2-8 x 40?
Let me assume that this equation is -2 -8x = 40 It's usually best to move all the purely numerical items to one side first. Let me move the -2. Then, to do this I add 2 to both sides. -2 - 8x +2 = -8x = 40 + 2 = 42 or -8x = 42 Now, to yield x 'by itself' let me divide both sides by -8. (-8x)/-8 = x = 42/(-8) = -21/4 or x = -21/4
Is -4(-3x-8)-4x 8 equal to -8x 40?
4
What are the solutions to the equations below (4x plus 36)(8x-40)0?
Assuming you mean:(4x+36)(8x-40) = 0 then you can use the property that a product can only be zero if one of its factors is zero. In other words, you can change this to: 4x + 36 = 0 OR 8x - 40 = 0 Solve each of the individual solutions; their solutions are also solutions to the original equation.
