4x+5 = 8x+10
But you are saying
4x+5 = 8x+4
If this were the case, 8x+10 = 8x+4, and so 10=4
Thus there is no possible solution for X.
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Honk! Go to your room.
8x + 4 = 4x + 5
Subtract 4x from each side:
4x + 4 = 5
Subtract 4 from each side:
4x = 1
Divide each side by 4:
x =1/4
Check:
Left side: 8x + 4 = 8/4 + 4 = 2 + 4 = 6
Right side: 4x + 5 = 4/4 + 5 = 1 + 5 = 6
6 = 6 yay!
8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4
-8x + 4 = -4x; (-8+4)x = -4; x = 1.
8x+2y=4x=-y/4+0.5y=-4x+2
8x-5=23+4x 8x-5-4x=23+4x-4x 4x-5=23 4x-5+5=23+5 4x=28 4x/4=28/4 x=7
8x+5=4x+17 4x=12 subtract 4x from right and 5 from left x=3 divide both sides by 4
8x + 12 = 4x - 4 8x - 4x = -4 - 12 4x = -16 x = -4
-8x + 4 = -4x; (-8+4)x = -4; x = 1.
8x+2y=4x=-y/4+0.5y=-4x+2
8x + 10 = 3x +145x = 4x = 4/5 = 0.8Improved answer:8x+10 = 4x+148x-4x = 14-104x = 4x = 1
8x+30=4x+18 -4x -4x 4x+30=18 -30 -30 4x=-12 4x/4=-12/4 x=-3
The value of x is 2
Only if 4 dollars plus 4 dollars equals 8 dollars.And if you had another 4x, you'd have a dozen-x.
8x-5=23+4x 8x-5-4x=23+4x-4x 4x-5=23 4x-5+5=23+5 4x=28 4x/4=28/4 x=7
8x+5=4x+17 4x=12 subtract 4x from right and 5 from left x=3 divide both sides by 4
16x2 + 8x + 1 = 0 : This factorises to (4x + 1)(4x + 1) = 0 When 4x + 1 = 0 then 4x = -1 : x = -1/4.
x = -8, y = 10
If: -9-4x = 7-8x Then: x = 4