(B/C) + (B/A) = 1
(1/B) = (1/A) + (1/C)
B = AC/(A + C)
This is the familiar lensmakers formula, or two resistors or inductors in parallel,
or two capacitors in series.
If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is
degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends
and the letter 'B' sticking out somewhere between them for no apparent reason.
Chat with our AI personalities
Commutativity.
It would be a straight line of length bc
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
It could be a vector sum.
You could conclude that B lies between A and C.