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(B/C) + (B/A) = 1

(1/B) = (1/A) + (1/C)

B = AC/(A + C)

This is the familiar lensmakers formula, or two resistors or inductors in parallel,

or two capacitors in series.

If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is

degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends

and the letter 'B' sticking out somewhere between them for no apparent reason.

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14y ago

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Q: AC equals AB plus BC
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