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A 747 airliner reaches its takeoff speed of 173 mih in 35.2 s. What is is the magnitude of its average acceleration?
Wiki User
∙ 11y ago
v = u + at
v = 173 mph
u = 0 mph (assuming taking off from rest)
t = 35.2 s
Thus: 173 = 0 + 35.2a
a = 173/35.2
a = 4.917777... mph/s
(To convert to m.s-2 multiply by 0.44704 => 2.198 m.s-2)
Wiki User
∙ 11y ago
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