Q: A car starts from rest and reaches 20 ms in 10 seconds The average acceleration of the car in ms2 is?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.

Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2

I assume the object starts from rest. The speed will be 16*3 which is 48m/s

Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s

veliocity = = acceleration x time v = at v = 150 km /hr = 150/60 km/minute t = 3 minutes a = v/t = 150/60/3 = 5/6 km/min/min = .833 km/min/min

Related questions

It is accelerating at 1.2m/s per second.

The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.

If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.

Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2

The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.

What do you mean "show your work" ? ! ?Did this question come from a homework assignment or something ?That's not an acceptable use of this website.Coach White's acceleration is 28.89 meters per second2, which is almost 3 G's.

2.0 m/s^2

I assume the object starts from rest. The speed will be 16*3 which is 48m/s

the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.

To determine the speed of the box after 10 seconds, we need to use the formula for acceleration: ( a = F / m ), where ( a ) is acceleration, ( F ) is the force, and ( m ) is the mass. Given that the force is constant and the box starts from rest, we can further use the equation for speed ( v = a * t ), where ( t ) is time. Calculate the acceleration using the force and mass, then use that acceleration to calculate the final speed after 10 seconds.

Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s

vf=54 km/hr vi=0km/hr t=5sec/0.001hr a=5400 km/hr 54km/hr- 0km/hr --------------------- 0.001 hr