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A car starts from rest and reaches 20 ms in 10 seconds The average acceleration of the car in ms2 is?
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If a car starts from rest and after 6 seconds it is moving at 42 ms what is the car's average acceleration?
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
A train starts from rest and increases its speed uniformly for the three minutes In that time it reaches 150 kilometers per hour What is its acceleration?
veliocity = = acceleration x time v = at v = 150 km /hr = 150/60 km/minute t = 3 minutes a = v/t = 150/60/3 = 5/6 km/min/min = .833 km/min/min
What is the average acceleration of a car that starts at rest and then moves straight ahead reaching 18 meters per second in 12 seconds?
It is accelerating at 1.2m/s per second.
A car starts at rest and attains a velocity of 15 meters per second in 5 seconds what is its acceleration?
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
If a car starts from rest and after 6 seconds it is moving at 42 ms what is the car's average acceleration?
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
A ball is dropped from a window and takes 2 seconds to reach the ground. It starts from rest and reaches a final speed of 20 MS What is the balls acceleration?
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
What is Coach Whites acceleration if he is known for rapid acceleration and he starts up from a stop sign and reaches thirteen meters per second in point forty five seconds show your work?
What do you mean "show your work" ? ! ?Did this question come from a homework assignment or something ?That's not an acceptable use of this website.Coach White's acceleration is 28.89 meters per second2, which is almost 3 G's.
If a car starts from rest and travels a distance of 100 meters in 10 seconds what is the car acceleration?
2.0 m/s^2
What is the acceleration of an object that starts stopped and after 5 seconds is going 25mm per hour?
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the acceleration of a body which starts from rest and travels 87.5 m in 5 seconds?
The acceleration of the body can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Since the body starts from rest, the initial velocity is 0 m/s. The distance traveled is 87.5 m in 5 seconds, so the final velocity can be calculated using the formula: final velocity = distance / time. Plugging in the values, we get final velocity = 87.5 m / 5 s = 17.5 m/s. Now, using the acceleration formula, we get: acceleration = (17.5 m/s - 0 m/s) / 5s = 3.5 m/sĀ².
A constant forces of ION pushes a 10 kg box of 10 seconds If the was initially at rest what its speed after 10 seconds?
To determine the speed of the box after 10 seconds, we need to use the formula for acceleration: ( a = F / m ), where ( a ) is acceleration, ( F ) is the force, and ( m ) is the mass. Given that the force is constant and the box starts from rest, we can further use the equation for speed ( v = a * t ), where ( t ) is time. Calculate the acceleration using the force and mass, then use that acceleration to calculate the final speed after 10 seconds.
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
