I think I know how to do this but I'm not sure...
It's something like:
A, B & C are consecutive so:
A=A, B=A+/-1, C=A+/-2
So:
A/(A+/-1)/(A+/-2)=0.3
I think it can be worked out from there but I'm not sure how...
There are two consecutive odd, whole numbers. The numbers are 39 and 41.
Consecutive numbers are whole numbers whose difference is 1.
7 and 8. You know that the sum of any two consecutive whole numbers, x and x +1, is 2x +1 2x + 1 = 15 2x = 14 x = 7
It is called a whole consecutive number.
No two consecutive whole numbers equal 0.5625 using the basic operations of arithmetic.
The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.
Consecutive whole numbers have no other whole numbers between them.
There are two consecutive odd, whole numbers. The numbers are 39 and 41.
The average of 33 consecutive whole numbers is 58, what is the smallest of these whole numbers? The answer is 42
The two consecutive whole numbers between 190 are 95 and 96. To find these numbers, you can divide 190 by 2, which equals 95. Since 95 is a whole number, the consecutive number after it is 96.
21/4 is not a whole number and it cannot be represented as consecutive whole numbers.
Consecutive numbers are whole numbers whose difference is 1.
The only two consecutive whole numbers that are prime numbers are 2 and 3. Otherwise, every second consecutive whole number in sequence is even, and being multiples of 2, they cannot be prime.
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
7 and 8. You know that the sum of any two consecutive whole numbers, x and x +1, is 2x +1 2x + 1 = 15 2x = 14 x = 7
It is called a whole consecutive number.
No two consecutive whole numbers equal 0.5625 using the basic operations of arithmetic.