Volume = 150.79645 in3
Volume = 301.59289 in3
The volume of sphere = (4/3)*pi*r3 where r is the radius. The diameter of a ping pong ball is 40 mm or 1.5478 in. the radius is 20 mm. r3 is 8000 mm3 The volume is 33510 mm3 or or 33.51 cc or 2.045 in3
Assuming the volume is 47.1 in3 and the radius is 3.0 in, then: volume_cone = 1/3 x π x radius2 x height ⇒ height = (3 x volume) ÷ (π x radius2) = (3 x 47.1 in3) ÷(π x (3.0 in)2) ≈ 5 in
The formula is 4/3 times pi (π) times the radius cubed. Radius is 1/2 the diameter. Diameter is 2 so radius is one. 4/3 * π * 13 4/3 * π * 1 4/3 * π =4.19 in3
20569.09 in3
Volume = 1,436.90165 in3
Volume = 1,436.90165 in3
Volume = 150.79645 in3
Volume = 1,436.90165 in3
Volume = 301.59289 in3
Volume = 3,468.31829 in3
Volume = 301.59289 in3
Volume = 301.59289 in3
Volume = 3,015.92895 in3
The formula for the volume (V) of a ball (a sphere) is V = 4/3πr3. As the diameter = 6 inches then the radius = 3 inches. V = 4/3π33 = 113.097 in3 (3dp)
The volume of sphere = (4/3)*pi*r3 where r is the radius. The diameter of a ping pong ball is 40 mm or 1.5478 in. the radius is 20 mm. r3 is 8000 mm3 The volume is 33510 mm3 or or 33.51 cc or 2.045 in3