Q: A boat travels due east for a distance of 15 miles it travels due north for a distance of 20 miles at which point it drops anchor how many milesis the boat from it?

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25 miles

This is a question based on Pythagoras. The answer is sqrt[(15)2 + (20)2] = 25 miles

25 miles

This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point

you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25 you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25

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This is a question based on Pythagoras. The answer is sqrt[(15)2 + (20)2] = 25 miles

25 miles

it drops anchor

Anchor Drops was created on 2004-06-29.

This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point

you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25 you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25

25 miles

-197 ft.