A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.
25 miles
25 miles
This is a question based on Pythagoras. The answer is sqrt[(15)2 + (20)2] = 25 miles
you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25 you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25
hm
25
A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.
25 miles
25 miles
This is a question based on Pythagoras. The answer is sqrt[(15)2 + (20)2] = 25 miles
5 miles
it drops anchor
25 miles
you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25 you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25
Anchor Drops was created on 2004-06-29.
-197 ft.