Jocampo36
hope im right...
dx/dt = 3.1 t
dx = 3.1 t dt
dx=52
z=distance
52= intergral(0,Z) 3.1 t dt
52=3.1 Z^2 /2
Z^2=104/3.1
Wiki User
∙ 14y agoSo it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
Since the car accelerates uniformly, its average speed during the interval is1/2 (initial speed + final speed) = 1/2 (4.15 + 17.11) = 10.63 m/s.The distance covered is (average speed) x (time) = (10.63) x (4.8) = 51.024 meters.If the motion during the 4.8 seconds was all in the same direction along a straight line,then that same 51.024 meters is also the displacement during that time.If, instead, it happened to take 4.8 seconds to go around a circle with a circumferenceof 51.024 m, then the displacement over the 4.8 seconds is zero, since the starting lineis also the finish line.
An arc, which is a uniformly curved line with a common radii point.
Straight means starting from one point and goes in same path and join at end point
A tangent at that point where a straight line just touches a curve and a secant line when the straight line bisects the curve.
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
Since the car accelerates uniformly, its average speed during the interval is1/2 (initial speed + final speed) = 1/2 (4.15 + 17.11) = 10.63 m/s.The distance covered is (average speed) x (time) = (10.63) x (4.8) = 51.024 meters.If the motion during the 4.8 seconds was all in the same direction along a straight line,then that same 51.024 meters is also the displacement during that time.If, instead, it happened to take 4.8 seconds to go around a circle with a circumferenceof 51.024 m, then the displacement over the 4.8 seconds is zero, since the starting lineis also the finish line.
The displacement is 6km because it is the straight-line distance from the starting point to the final point. The displacement represents the shortest path between the two points, regardless of the actual distance traveled.
loads are carried out as point load uniformly distributed load and uniformly varying load
The distance moved by an object is the total length of the path traveled, while the displacement vector is the shortest distance between the starting and ending points in a straight line. Therefore, the distance moved can be greater than or equal to the displacement vector, depending on the path taken by the object.
A straight line is usually faster than a zigzag route when traveling from one point to another. Zigzagging increases the overall distance traveled and can result in a longer travel time compared to a straight path.
The displacement of the driver is 6 km because it measures the straight-line distance between the starting point and the final position, regardless of the path taken in between.
An arc, which is a uniformly curved line with a common radii point.
distance from point x to point y, not the distance that traveled.
The slope at each point on a speed/time graph is themagnitude of acceleration at that point in time.
Speed at a given point in time refers to the rate at which an object is moving at a specific instant. It is often calculated by determining the distance traveled by an object divided by the time it took to cover that distance. Speed can vary over time as an object accelerates or decelerates.
Terminal velocity is the point at which air resistance and gravity are balanced so that a falling object no longer accelerates. At this point, the object falls at a constant speed because the force of air resistance is equal to the force of gravity acting on the object.