The time it takes to execute this maneuver is [ 200 / (average of 40 and 80) ] = [ 3 and 1/3 ] seconds.
Acceleration = (change in speed) / (time for the change)
= 20/(3 and 1/3) = 20/(10/3) = 20 x (3/10) = 60/10 = 6 meters/sec2 = about 0.61 G
Average acceleration = change in speed/time for the change = 15/5 = 3 meters per second2 .
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
5.0 meters every second.
Acceleration is not measured in meters/second. Meters/second is a unit of speed. Since acceleration is defined as change of speed divided by time, the units are meters/second/second, usually written as meters/second2.
Average acceleration = (change in speed) divided by (time for the change) =(15 - 0) / (5) = 15/5 =3 meters per second2
Assuming you want the international units: time: second velocity: meters / second distance: meters acceleration: meters / second2
Average acceleration = change in speed/time for the change = 15/5 = 3 meters per second2 .
The average acceleration can be calculated using the formula: acceleration = (change in velocity) / (time taken). In this case, the change in velocity is 20 m/s - 16 m/s = 4 m/s and the distance is 36 meters. Since time is not provided, the acceleration cannot be determined.
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
5.0 meters every second.
.052 meters per second or .09 per meter
Acceleration is not measured in meters/second. Meters/second is a unit of speed. Since acceleration is defined as change of speed divided by time, the units are meters/second/second, usually written as meters/second2.
Average acceleration = (change in speed) divided by (time for the change) =(15 - 0) / (5) = 15/5 =3 meters per second2
In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2
It is acceleration that is measured in distance per unit of time per unit time, or in meters per second per second, as the question asked. The only thing missing is the direction vector.
-- Your speed after 30 seconds will be 30 meters per second.-- Since your acceleration is constant, your average speed during the 30 secondsis the average of your initial and final speed . . . 15 meters per second.-- The distance you cover is your average speed for 30 seconds = 15 x 30 = 450 meters.
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.