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A car starts from rest and reaches 20 ms in 10 seconds The average acceleration of the car in ms2 is?
10
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
A pitcher takes 0.10 seconds to throw a baseball which leaves his hand with a velocity of 40 seconds What is the ball's acceleration?
To find the acceleration of the baseball, we can use the formula ( a = \frac{\Delta v}{\Delta t} ). Here, the change in velocity (( \Delta v )) is 40 m/s (since it starts from rest), and the time interval (( \Delta t )) is 0.10 seconds. Thus, the acceleration is ( a = \frac{40 , \text{m/s}}{0.10 , \text{s}} = 400 , \text{m/s}^2 ).
A car starts from rest and reaches 20 ms in 10 seconds The average acceleration of the car in ms2 is?
10
What is the average acceleration of a car that starts at rest and then moves straight ahead reaching 18 meters per second in 12 seconds?
It is accelerating at 1.2m/s per second.
A car starts at rest and attains a velocity of 15 meters per second in 5 seconds what is its acceleration?
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What happens if Something is traveling at constant deceleration?
It slows to a rest and then starts moving in the opposite direction at constant acceleration in that direction.
If a car starts from rest and travels a distance of 100 meters in 10 seconds what is the car acceleration?
2.0 m/s^2
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the acceleration of an object that starts stopped and after 5 seconds is going 25mm per hour?
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
Is it possible for an object with constant negative acceleration to change the direction in which it is moving?
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
A constant forces of ION pushes a 10 kg box of 10 seconds If the was initially at rest what its speed after 10 seconds?
To determine the speed of the box after 10 seconds, we need to use the formula for acceleration: ( a = F / m ), where ( a ) is acceleration, ( F ) is the force, and ( m ) is the mass. Given that the force is constant and the box starts from rest, we can further use the equation for speed ( v = a * t ), where ( t ) is time. Calculate the acceleration using the force and mass, then use that acceleration to calculate the final speed after 10 seconds.
What is a real life example of acceleration?
You have acceleration any time a velocity changes - like when an object falls down due to gravity, when a car starts or stops, when you start moving or stop moving, etc.
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
