Magnitude of average acceleration = (change of speed) divided by (time for the change)
Average 'A' = (16 - 6) / 240 seconds = 10/240 = 1/24 meter per second2
-- That's the average over the 4 minutes. We don't know anything about the
value of the acceleration at any particular instant during the 4 minutes..
-- We're working entirely with scalars ... speed, not velocity, and magnitude of
acceleration ... since we don't know anything about the car's direction at any
point in time during the whole event.
zero - it is constat velocity. so acceleration is zero50 m/s2 Another : The acceleration is ZERO. Acceleration is defined as the change in velocity per unit time. If the ball is traveling a constant velocity over a two minute period, the acceleration would be zero since there is no change in velocity.
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
Velocity = Distance ÷ Time Average Velocity = (10 + 10) ÷ (1/3 + 1/2) = 20 ÷ 5/6 = 20 x 6/5 = 24 mph NOTE : The times in minutes have been converted into fractions of an hour to enable the answer to be provided in miles per hour.
As the acceleration is uniform, the train has an average speed that is half the difference between the start and final velocities, which in this case is half the final velocity. 1 hr = 60 min 1 km/h = 1 km ÷ 1 hr = km ÷ 60 min = 1/60 km/min Distance = velocity × time = (½ × 72 × 1/60 km/min) × (5 min) = 36/60 × 5 km = 3 km
Constant velocity means the object is moving at a consistent speed in a straight line with no change in direction. Average velocity, on the other hand, takes into account changes in velocity over a given time interval and is calculated as the total displacement divided by the total time elapsed.
The acceleration of the body was zero during this interval because its velocity was constant. Acceleration is the rate of change of velocity, so if the velocity does not change, the acceleration is zero.
The acceleration is zero since the object is moving at a constant velocity. Acceleration is the rate of change of velocity, and in this case, the velocity is not changing.
1). If neither speed nor direction are changing, then acceleration is zero.2). "minutes" is not a unit of velocity, but we get the idea
If the ball is traveling at a constant velocity of 50 m/s, then its acceleration is 0 m/s^2. Acceleration is the rate of change of velocity, so if the velocity is constant, there is no change in velocity, and therefore no acceleration.
zero - it is constat velocity. so acceleration is zero50 m/s2 Another : The acceleration is ZERO. Acceleration is defined as the change in velocity per unit time. If the ball is traveling a constant velocity over a two minute period, the acceleration would be zero since there is no change in velocity.
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
The total displacement is 0 km, as the student returns to the starting point. The total time taken is 5 minutes + 7.1 minutes = 12.1 minutes. Therefore, the average velocity is 0 km divided by 12.1 minutes, which equals 0 km/min.
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
Think of average velocity as "overall" velocity. For example, if I walk down the block (let's say it's a distance of 100 meters), and it takes me 5 minutes, my AVERAGE velocity is just:v_ave = Δx/Δtwhere Δx is the change in position and Δt is the elapsed time.v_ave = (100 m) / (5 min)v_ave = (100 m) / (300 sec)v_ave = (1/3) m/sBut instantaneous velocity is a different concept: let's say for a while I walked, then I jogged, then I stopped, then I sprinted, then I walked. The overall trip still ended up taking me 5 minutes, so my average velocity is just as I've calculated it above, but my INSTANTANEOUS velocity changes as I change speeds at any given time in between.Hope this helps!
To find the rate of deceleration, we first need to convert the time from minutes to seconds. 3 minutes = 180 seconds. Next, we use the equation of motion: final velocity^2 = initial velocity^2 + 2 * acceleration * distance. Since the boat comes to a stop, the final velocity is 0 m/s. Substituting the values and solving for acceleration, we get a deceleration rate of 0.139 m/s^2.
Average speed = Distance/Time = 2.5 miles/15 minutes = 10 miles per hour