1st you must turn the meters into miles or the mph into meters per hour. I will turn the meters into mi. So, 1 meter = 6.214*10^-4 miles. You get the truck's equation is y=70x, the car's equation is y=50x+20*6.214*10^-4 because its 20 meters ahead of the truck.
Set them equal to each other and you get
70x=50x+20*6.214*10^-4 ----> subtract 50x from both sides, and you get:
20x = 20*6.214*10^-4 -------> divide both sides by 20 to leave x with a coefficient of 1:
x = 6.214*10^-4 -----------> that's the portion of an hour which it would take you. If you consider each hour has 60 minutes, you multiply x by 60 and you get the answer in minutes.
60*6.214*10^-4 = 3.72*10^-2 if you multiply that by 60 you get the answer in seconds:
60*3.72*10^-2 =2.23.
So there, it would take the truck 2.23 seconds to get to the car.
That depends on how fast the truck is traveling.
about a truck
In meters. A fairly long truck might just be a little over 20 meters long. Still a lot less than a kilometer.In meters. A fairly long truck might just be a little over 20 meters long. Still a lot less than a kilometer.In meters. A fairly long truck might just be a little over 20 meters long. Still a lot less than a kilometer.In meters. A fairly long truck might just be a little over 20 meters long. Still a lot less than a kilometer.
The answer is yes because centiMeters is not correct
250 miles
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.
an hour and one minute
One hour
One hour
The car is gaining on the truck, and the space between them is closing, at (96-75) = 21 km/hr.The car will overtake the truck in (100/21000) hour = (60/210) minutes = (3600/210) = 17.143 seconds (rounded)
If a car and a truck are traveling at the same speed, the truck would have more momentum because it has a greater mass.
the truck behind the other car
The kinetic energy of the truck can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the truck and v is its velocity. First, convert 22500 lb to kg (1 lb ≈ 0.4536 kg) and 55 mph to m/s (1 mph ≈ 0.44704 m/s). Then plug the values into the formula to calculate the kinetic energy in joules.
That depends on how fast the truck is traveling.
It is zero, since at constant velocity there is no acceleration. If 12000N are resisting motion, the truck is putting out 12000 N in opposite direction.
Depends on the size of the truck, the purpose, the distance it'll be traveling, the area in which it will be traveling, etc. Too many unaddressed variables to give an accurate answer here.
jump in front of truck traveling 75 miles semi truck