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92km/h = 41*5/3*3 =205/9m/s

v = 205/9 m/s
u = 0m/s
s = 0.85m = 85/100m
a = ?

v2 = u2 + 2as
=> 2052/81 = 2 * a * 85/100
=>a = -0.9766m/s2

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Q: A car traveling at 92 kmh strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.85 m. What was the average acceleration of the driver during the collision?
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A car traveling at 25 meters a second speeds up to 40 meters a second over a period of 15 seconds what is the average acceleration of the car?

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Related questions

A car traveling at 25 meters a second speeds up to 40 meters a second over a period of 15 seconds what is the average acceleration of the car?

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