You would cut off a corner.
A hexahedron is a three-dimensional figure with six identical faces - in other words, a cube. So a hexahedron is not made up of hexagons at all, but of squares. However, if you were to balance a cube on one of the vertices, the horizontal plane cutting the cube in half would make a cut in the shape of a regular hexagon. Four such regular hexagons can be found in the cube.
None, but you can cut a cube into any number ≥ 2 of triangular prisms.
The answer will depend on how many corners have been cut off in the truncation process.
I think no because a cube is a perfect 3D square and if you cut it it becomes a rectangle type thing
A pentagonal prism, a hexagonal pyramid, a cube with one vertex (corner) cut off, a tetrahedron with three vertices cut off - these are some of the possibilities.
You would cut off a corner.
A hexahedron is a three-dimensional figure with six identical faces - in other words, a cube. So a hexahedron is not made up of hexagons at all, but of squares. However, if you were to balance a cube on one of the vertices, the horizontal plane cutting the cube in half would make a cut in the shape of a regular hexagon. Four such regular hexagons can be found in the cube.
None, but you can cut a cube into any number ≥ 2 of triangular prisms.
8 corners will be left
There are an infinite number of possible solutions. A tetrahedron and icosahedron are regular shapes. Then there is the triangular prism. A cuboid with one vertex cut off, a cube with 2 vertices cut off, 3 vertices etc. In fact, cutting off the vertex of any polyhedron in which three sides (faces) meet at the vertex will give a new triangular face.
The answer will depend on how many corners have been cut off in the truncation process.
Five
can have any no depending on how its cut
I think no because a cube is a perfect 3D square and if you cut it it becomes a rectangle type thing
Julienne, slice, mince, chop, dice & cube.
Five