the no of vertices will be 1+1+1+1+1+1+1+3=10
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You would cut off a corner.
A hexahedron is a three-dimensional figure with six identical faces - in other words, a cube. So a hexahedron is not made up of hexagons at all, but of squares. However, if you were to balance a cube on one of the vertices, the horizontal plane cutting the cube in half would make a cut in the shape of a regular hexagon. Four such regular hexagons can be found in the cube.
None, but you can cut a cube into any number ≥ 2 of triangular prisms.
The answer will depend on how many corners have been cut off in the truncation process.
I think no because a cube is a perfect 3D square and if you cut it it becomes a rectangle type thing