Wiki User
∙ 14y agoSince , V = u + at,
we get , a = v - u /t
= 402.3 - 0 /9.013
= 44.6355264617 ms-2
Therefore, acceleration = 44.6355264617 ms-2
Wiki User
∙ 14y agoAssuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
Acceleration is a change in velocity. Assuming a constant direction, if you're speeding up that is positive acceleration. If you are slowing down, that's negative acceleration. Either way you are accelerating.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
Assuming (a) an initial velocity of zero, and (b) constant acceleration, the formula becomes: distance = 0.5 at2 (distance = 1/2 times acceleration times time squared).
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
First, calculate the acceleration using the formula acceleration = net force / mass. Plug in the values to get acceleration. Next, use the kinematic equation, displacement = (initial velocity * time) + (0.5 * acceleration * time^2), where initial velocity is 0 since the cart starts at rest. Plug in the calculated acceleration and time to find the displacement of the shopping cart.
As the ball falls from the tower, it accelerates due to gravity. Its downward velocity increases as it falls, while its potential energy decreases. The ball's acceleration is approximately 9.81 m/s^2 (assuming no air resistance).
The vehicle accelerates, assuming the engine is in a vehicle.
Acceleration is the CHANGE in velocity; you're assuming CONSTANT velocity. So the acceleration is zero.
No, mass and acceleration are not directly proportional. Acceleration is inversely proportional to mass, meaning that an increase in mass will result in a decrease in acceleration, assuming the applied force remains constant.
Assuming the mass remains constant, the acceleration will be tripled as well.
The radial acceleration of the planet Mercury can be calculated using the formula for centripetal acceleration, which is given by v^2/r, where v is the velocity of Mercury and r is the distance from Mercury to the Sun. Mercury's high orbital velocity and close proximity to the Sun result in a significant radial acceleration compared to other planets in the solar system.
Newton's second law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. This can be expressed as the equation F = ma, where F is the force, m is the mass, and a is the acceleration. By knowing the mass of an object and the acceleration it experiences, you can use this equation to calculate the force acting on the object.