In C/C++, this code
int a = 5;
return a+++++a;
leads to error. However, writing
int a = 5;
return (a++ + ++a);
returns 12. Note that in other languages "a=5; a+++++a" leads to different results :)
b = -6
b= 10
If: b/5+b/3 = 10 then b works out as 18.75
Not enough information to solve
Yes because if 1+0=1 than 0 plus b equals b
3
b= 10
b = -6
b= 10
If: b/5+b/3 = 10 then b works out as 18.75
We are given that a + b = -7 and b = 10 Therefore a +10 = =7 Subtract 10 from each side So a + 10 - 10 = -7 + 10 Which simplifiesn to a = 10 - 7 So a = 3
Not enough information to solve
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
the answer is a
Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.