a+b+c+d+e = 30 (i)
c+e = 14 (ii)
d+b = 1 (iii)
a = 2b-1 (iv)
a+c = 10 (v)
By (i)-(ii)-(iii): a = 15
then, by (iv): b = 8
and by (v): c = -5
Also, b = 8 so by (iii): d = -7
and then by (i), e = 19
n = 3/2, n = 2
Probably
They are identities because they are true for ALL values of w and x.
2048
That is an impossible equation, because it is stating that m has two values.
x=-3y=4
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
-2
Two plus eleven = thirteen.
The values are: x = -6 and y = 10
Decomposition into decimal digits (or separating out into place values).
cup
9
Any two values which total 25
That depends what the values of k and b are.
The letters 'y', 'm', 'x' plus 'b' in mathematics mean a specific number in an algebraic equation. The objective is to work out what the values of the letters are.
144 (square the first value and add the product of the two values). In the statement 7 + 6 should = 91, not 63, which would be 7 + 2.