Wiki User
∙ 2009-10-13 13:37:11a+b+c+d+e = 30 (i)
c+e = 14 (ii)
d+b = 1 (iii)
a = 2b-1 (iv)
a+c = 10 (v)
By (i)-(ii)-(iii): a = 15
then, by (iv): b = 8
and by (v): c = -5
Also, b = 8 so by (iii): d = -7
and then by (i), e = 19
Wiki User
∙ 2009-10-13 13:37:11n = 3/2, n = 2
2048
They are identities because they are true for ALL values of w and x.
Probably
That is an impossible equation, because it is stating that m has two values.
x=-3y=4
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
That's going to depend on the values of 'a', 'b', 'c', and 'f'.
-2
Two plus eleven = thirteen.
The values are: x = -6 and y = 10
Decomposition into decimal digits (or separating out into place values).
9
cup
Any two values which total 25
That depends what the values of k and b are.
The letters 'y', 'm', 'x' plus 'b' in mathematics mean a specific number in an algebraic equation. The objective is to work out what the values of the letters are.