A very good try, but f(n) is still ambiguous. I assume you mean f(n) = 1/2*n*(n+2) and not 1/[2*n*(n+2)] Then f(n+2) - f(n) = 1/2*(n+2)*(n+2+2) - 1/2*n*(n+2) = 1/2*(n+2)*(n+4) - 1/2*n*(n+2) = 1/2*(n+2)*{(n + 4) - n} = 1/2*(n+2)*4 = 2*(n+2)
F(n) = 4n
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
Perfect squares have an odd number of factors. If f is a factor of N, then so is N/f. (For example, 3 is a factor of 30, and so is 10). Thus, it seems factors come in pairs, and there should always be an even number of them. But if f = N/f, then these two factors are the same, resulting in an odd number of factors. For example, 3 is a factor of 9, and it's "mate" is also 3. So for the numbers with an odd number of factors, there is some f where f=N/f. Multiplying both sides by f, we have f^2 = N. So this happens when N is a perfect square.
There is no limit in a number. There is however a mathematical concept known as a limit but this applies to functions. For instance: The limit of f(n)=(1/n) as n goes to infinity is 0. The limit of f(n)=(n/n) as n goes to infinity is 1.
Suppose N is a perfect number. Then N cannot be a square number and so N has an even number of factors.Suppose the factors are f(1) =1, f(2), f(3), ... , f(k-1), f(k)=N.Furthermore f(r) * f(k+1-r) = N for r = 1, 2, ... k so that f(r) = N/f(k+1-r)which implies that 1/f(r) = f(k+1-r)/NThen 1/f(1) + 1/(f(2) + ... + 1/f(k)= f(k)/N + f(k-1)/N + ... + f(1)/N= [f(k) + f(k-1) + ... + f(1)] / N= 2N/N since, by definition, [f(k) + f(k-1) + ... + f(1)] = 2N
Given an integer n, an integer f is a fraction of n if f goes into n evenly. That is, n/f is an integer or n = f*x for some integer x.m is a multiple of n if m = n*c for some integer c.
#include#includeint a,f,n,sum=0; printf("Enter any number"); scanf("%d",&n); f=1; for(a=1;a<=n;a ); { f=f*a; } for(f=1;f<=n;f ); { sum=sum f; } printf("sumation of factorial numbers :",sum); getch(); }
The height of F n F Tower at Panama City in Panama is 243 m.
N. F. Simpson was born in 1919.
N. F. Varghese was born in 1949.
A very good try, but f(n) is still ambiguous. I assume you mean f(n) = 1/2*n*(n+2) and not 1/[2*n*(n+2)] Then f(n+2) - f(n) = 1/2*(n+2)*(n+2+2) - 1/2*n*(n+2) = 1/2*(n+2)*(n+4) - 1/2*n*(n+2) = 1/2*(n+2)*{(n + 4) - n} = 1/2*(n+2)*4 = 2*(n+2)
f = {n : n Î Z, n ≥ 12}
<html> <script language="vbscript"> n=cint(inputbox("Enter a number")) dim f f=1 if n<0 then Msgbox "Invalid number" elseif n=0 or n=1 then MsgBox "The factorial of given number "&n&" is :"&f else for i=n to 2 step -1 f=f*i next MsgBox "The factorial of given number "&n&" is :"&f end if </script> </html>
this is not correct F F F F F F F G A G F F F G F A N D A A J B E D J I N G
N. F. Pavlov has written: 'Povesti i stikhi'
N. F. Golubov has written: 'Golovnye boli'