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The correct answer is a) empirical formula mass. The molar mass of a compound is often a whole number multiple of its empirical formula mass, as the empirical formula represents the simplest whole-number ratio of the elements in the compound, while the molar mass reflects the total mass of a mole of its molecules or formula units.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
The law of constant proportion states that a pure chemical compound always contains exactly the same proportion of elements by mass.This information, together with the atomic masses of the elements in the compound enable scientists to determine the formula of a compound.
An empirical formula represents the simplest whole-number ratio of the elements in a compound. Therefore, any formula that includes non-integer ratios or fractional subscripts is definitely not an empirical formula. For example, a formula like C2H5, which can be simplified to C1H2.5, is not an empirical formula because it contains a fractional subscript.
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.
Acetylene is C2H2 so its emperical formula is C1H1.
what is the empirical formula for water H2O
Silver oxide is an ionic compound so its molecular and empirical formula is same Ag2O
It is an empirical formula.
F6 refers to the molecular formula of a compound, indicating that it contains six fluorine atoms. An empirical formula represents the simplest whole-number ratio of the elements in a compound; for F6, the empirical formula would be F, as it indicates the presence of fluorine without specifying the number of atoms. Thus, F6 is not an empirical formula, but rather a molecular one.
Because an empirical formula is the simplest form of a compound, we know that the molecular formula contains more atoms than it does. Since we are given the molar mass, we can use this formula. x ( MM of empirical formula ) = MM of molecular formula MM of empirical formula = 12(2) + 1(6) + 16 = 46 MM of molecular formula = 138 46x = 138 x= 138 / 46 x=3 Therefore, the molecular formula is 3(C2H6O) that is C6H18O3
The empirical formula for deoxyribose is CH2O. This formula represents the simplest whole-number ratio of carbon, hydrogen, and oxygen atoms in the molecule. Deoxyribose, a sugar component of DNA, specifically contains five carbon atoms, leading to the molecular formula C5H10O4. However, its empirical formula reduces to the simplest form CH2O.
CH will be the empirical formula and C12H12 will be the molecular formula
A formula unit is an empirical formula.
It Has No Empirical Formula.