You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles.
80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C
20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H
the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C
19.84 moles H/6.66 moles C
= 2.9, which we call 3
so,
CH3
---------------
is the empirical formula
To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide.
Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
Density of a substance = (mass of a sample of the substance) divided by (volume of the same sample)
NO2 is the molecular formula for NO2.
You would have a very tough time, because that isn't the formula to calculate work. (distance) divided by (time) is the formula to calculate speed. The formula to calculate work is: (force) multiplied by (distance).
The conversion of milliequivalents (mEq) to milligrams (mg) depends on the substance being measured and its molecular weight. The formula to convert mEq to mg is: mg = mEq × (molecular weight in mg/mEq). For example, for potassium (with a molecular weight of approximately 39.1 mg/mmol), 1 mEq of potassium equals about 39.1 mg. Always ensure to use the correct molecular weight for the specific ion or compound in question.
an is a built in formula that uses arguments to calculate information. is FUNCTION
A formula unit.
A formula unit.
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
Yes, it is possible for a substance to have the same empirical and molecular formula. This can occur when the substance is composed of only one type of element, such as oxygen gas (O2), where both the empirical and molecular formula are O2.
To calculate the empirical formula from a molecular formula, divide the subscripts in the molecular formula by the greatest common factor to get the simplest ratio of atoms. This simplest ratio represents the empirical formula.
Ag is the molecular formula for silver. If you look on a periodic table, you will find this substance with the transitional metals and with the atomic number of 47.
To convert micrograms to micromoles, you need to know the molecular weight of the substance. The formula to convert micrograms to micromoles is: Micromoles = (micrograms / molecular weight) If you provide the molecular weight of the substance, I can help you calculate the number of micromoles in 20 micrograms.
To calculate parts per million (ppm) from molecular weight, you first need to know the mass of the substance in grams per mole. Then, you can use the formula: ppm = (mass of substance in grams / total mass of mixture in grams) * 10^6. This will give you the concentration of the substance in parts per million.
The identity of a substance (chemical compound) is defined by his chemical formula and molecular structure.
Density can be calculated from molecular weight using the formula density = (molecular weight) / (molar volume). Molar volume is the volume occupied by one mole of the substance and can be calculated using the ideal gas law or experimental data. Dividing the molecular weight by the molar volume gives the density of the substance.
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
To calculate the molecular formula from the empirical formula, you need to determine the molecular mass of the compound and then divide it by the empirical formula mass to find the factor between the two. If the factor is 6, it means the molecular formula is 6 times the empirical formula, indicating that there are 6 times as many atoms of each element in the molecular formula compared to the empirical formula.