You want: P(even) * P(even) * P(even) * P(even). P(even) = 3/6 or 1/2. Therefore probability even on 4 rolls is: 1/2 * 1/2 * 1/2 * 1/2 = 1/16 = 0.0625.
The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.
It is 0.722... recurring.
The probability is 0.6187, approx.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on how many times it is rolled.
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.
It is 0.722... recurring.
The probability is 0.6187, approx.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on how many times it is rolled.
15
25/36
The probability that 14 is rolled at least once is 1 - 5.5*10-32 which, for all intents and purposes, can be treated as 1.
3_18 3_18
1/12 possibilty.
1:4 i think