well its all 50% no matter what
It is 1 - 0.3120 = 0.6880, approx.
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
The probability of getting an even number on at least one of the 3 rolls is 7/8.
The probability is 0.6187, approx.
The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.
It is 0.722... recurring.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on how many times it is rolled.
The chance of any 1 number appearing in a die roll 3 times in a row is: 1/6 * 1/6 * 1/6 which is 1/216 = .00463
The probability that 14 is rolled at least once is 1 - 5.5*10-32 which, for all intents and purposes, can be treated as 1.
1:4 i think
If you rolled a die 120 times, the probability of getting a 6 is one in six. It does not matter how many times you roll the die - the probability is still one in six - except that the long term mean will approach the theoretical value of 0.166... as the number of trials increases.