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What is the probabilty of throwing a 6 on a dice?
On a fair die, it is 1/6 on a single throw.On a fair die, it is 1/6 on a single throw.On a fair die, it is 1/6 on a single throw.On a fair die, it is 1/6 on a single throw.
If you roll a fair die four times what is the probability of rolling a four on only the second throw?
The probability of rolling a 4 when you throw once a fair die is: P(4) = 1/6.The probability of not rolling a 4 when you throw once a fair die is: P(NO 4) = 5/6.If you roll a fair die four times, the probability of rolling a four on only the secondthrow is:P(NO 4, 4, NO 4, NO 4) = (5/6)(1/6)(5/6)(5/6) = 0.096450617... ≈ 9.6%
What is the probability of scoring a four on a die?
If you throw a fair die one time, the chance of a four is 1/6 or about .1667
What is the probability that you roll a number less than five?
The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.
Two fair dice are each numbered so that they have the numbers 1 3 5 7 9 and 11 how many ways are there of scoring a total of 16?
5 + 11 11 + 5 7 + 9 9 + 7 So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are: Throw die #1 16 times and get 1 each time. Throw die #2 16 times and get 1 each time. Throw die # 1 13 times and get 1 13 times and 3 once. Throw die # 2 13 times and get 1 13 times and 3 once. Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3. Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1. You get the idea, figure out the rest yourself.
