The area is: 24.99
The area is approximately 22.91 units2
If the hypotenuse has been rounded to 2 decimal places then using Pythagoras the length of the other leg is also 10 cm. Area of the triangle: 0.5*10*10 = 50 square cm
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
4.930517214 cm (with the help of Pythagoras)
a^2+b^2=c^2 a^2+7^2=10^2 a^2+49=100 a^2=51 Simplified a=7.14
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
The area is approximately 22.91 units2
If the hypotenuse has been rounded to 2 decimal places then using Pythagoras the length of the other leg is also 10 cm. Area of the triangle: 0.5*10*10 = 50 square cm
6
square root of 46
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
The hypotenuse must be longer than the other other leg.
The hypotenuse is always the longest of the three sides of a right triangle.
4.930517214 cm (with the help of Pythagoras)
The area is 120 units2
a^2+b^2=c^2 a^2+7^2=10^2 a^2+49=100 a^2=51 Simplified a=7.14
For isosceles triangle both legs are the same, 10 cm. The hypotenuse is square root of sum of legs squared, = sqrt (10 squared + 10 squared) = 14.1 cm