The area is: 24.99
The area is approximately 22.91 units2
If the hypotenuse has been rounded to 2 decimal places then using Pythagoras the length of the other leg is also 10 cm. Area of the triangle: 0.5*10*10 = 50 square cm
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
4.930517214 cm (with the help of Pythagoras)
a^2+b^2=c^2 a^2+7^2=10^2 a^2+49=100 a^2=51 Simplified a=7.14
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
The area is approximately 22.91 units2
If the hypotenuse has been rounded to 2 decimal places then using Pythagoras the length of the other leg is also 10 cm. Area of the triangle: 0.5*10*10 = 50 square cm
6
square root of 46
The hypotenuse must be longer than the other other leg.
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
The hypotenuse is always the longest of the three sides of a right triangle.
4.930517214 cm (with the help of Pythagoras)
The area is 120 units2
For isosceles triangle both legs are the same, 10 cm. The hypotenuse is square root of sum of legs squared, = sqrt (10 squared + 10 squared) = 14.1 cm
a^2+b^2=c^2 a^2+7^2=10^2 a^2+49=100 a^2=51 Simplified a=7.14