No it isn't a perfect cube since if you start with 3, (3*3*3=27) and go to 4, (4*4*4=64) there isn't a number that multiplies by itself 3 times to equal 50.
y = 3 in the equation 31 = 4 - 9y Solve for y. 31 - 4 = 4 - 9y - 4 Simplify 27 = 9y Divide both sides by 9 to get the term y by itself on one side of the equation. 27 / 9 = 9y / 9 Simplify 3 = y
27/36 = 27 ÷ 36 = 0.75 27 ÷ 9 = 3 36 ÷ 9 = 4 ⇒ 27/36 = 3/4 (= 0.75)
3/4 of 36 is 27
0.1481
A number, x, multiplied by itself once is x^2. It is NOT x.The number, x, multiplied by itself twice is then x^3.The number, x, multiplied by itself three times is then x^4.Thus x is the 4th root of 27.So x = 27^(1/4) = +/- 2.2795 and +/- 2.2795*i where i is the imaginary square root of -1.
36
x + 1 = y y + 3 = z z = y + 3 = (x + 1) + 3 = x + 4 Or: x = y - 1 = (z - 3) - 1 = z - 4 Which results in the same: x exceeds z by 4.
No it isn't a perfect cube since if you start with 3, (3*3*3=27) and go to 4, (4*4*4=64) there isn't a number that multiplies by itself 3 times to equal 50.
Order of operations. Division comes before addition. 27/3 + 4 9 + 4 = 13 Or......... if you meant.... 27/(3 + 4) 27/7 = 27/7
6 3/4 = 27/4 (27/4) / 2 = 27/4 * 1/2 = 27/8 = 3 3/8
an exact divisor of a number is one that leaves no remainder (a remainder of zero)--example: 27 divided by 3 is 9 but 27 divided bt 4 is 6 remainder 3 so 4 is not an exact divisor of 27 but 3 is
27/4 = (24+3)/4 = 24/4 + 3/4 = 6+3/4 = 63/4
y = 3 in the equation 31 = 4 - 9y Solve for y. 31 - 4 = 4 - 9y - 4 Simplify 27 = 9y Divide both sides by 9 to get the term y by itself on one side of the equation. 27 / 9 = 9y / 9 Simplify 3 = y
27/4 is equal to 6.75 or 6 3/4
27/36 = 27 ÷ 36 = 0.75 27 ÷ 9 = 3 36 ÷ 9 = 4 ⇒ 27/36 = 3/4 (= 0.75)
3/4 of 36 is 27