30.
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There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Any number that is divisible by both 2 and 3 is divisible by 6.
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
The smallest number that is divisible by 5, 6, and 7 is 210.