the axis of symmetry
The highest or lowest point of the parabola, it is the point that is closest to the focus. The extreme point lies on the axis of symmetry
y = ax^2 + c where a and c are constants and a is not 0.
"Any light beam moving vertically downwards in the concavity of the parabola (parallel to the axis of symmetry) will bounce off the parabola moving directly towards the focus." http://en.wikipedia.org/wiki/Parabola
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
Its extremum is on its axis of symmetry.
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).
The axis of symmetry is x = -2.
There's the vertex (turning point), axis of symmetry, the roots, the maximum or minimum, and of course the parabola which is the curve.
the axis of symmetry
The highest or lowest point of the parabola, it is the point that is closest to the focus. The extreme point lies on the axis of symmetry
K
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Line of symmetry: x = 3
x=-b/2a [negative B over 2A]