How about y = (x - 2)2 = x2 - 4x + 4 ?
That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2.
Its vertex is located at the point (2, 0).
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
y = (x-4)(x-4) * * * The factors above are shown correctly. The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0). The equation of that line is x = 4, which is the answer you requested.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
If you ignore the print, then it has a plane of symmetry (possibly) but not an axis of symmetry. If you ignore the print and the "pop-top" part, then it has both.
The equation y = -2.5 represents a horizontal line on the Cartesian plane passing through the point (-2.5, 0). This line is parallel to the x-axis and has a slope of 0. The solution to this equation is all real numbers on the y-axis that have a value of -2.5.
Line of symmetry: x = 3
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
Its extremum is on its axis of symmetry.
x=-b/2a [negative B over 2A]
y = ax^2 + c where a and c are constants and a is not 0.
Yes, it does.
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).
The axis of symmetry is x = -2.
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
A parabola that opens upward is a U-shaped curve where the vertex is the lowest point on the graph. It can be represented by the general equation y = ax^2 + bx + c, where a is a positive number. The axis of symmetry is a vertical line passing through the vertex, and the parabola is symmetric with respect to this line. The focus of the parabola lies on the axis of symmetry and is equidistant from the vertex and the directrix, which is a horizontal line parallel to the x-axis.