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We have

6y=x3+2

y=x3/6+2/6

dy/dx=3x2/6+0=x2/2

We are interseted in finding the points for which the y-coordinate changes 8 times as the x-coordinates,so let

dy/dx=8

(2)=> x2/2=8

=>x2=16

=>x=+- 4

x=4=>y=4(3)/6+1/3=64/6+1/3=66/6=11

x=-4=>y=-4 (3)/6+1/3=-64/6+1/3=-62/6=-31/3

.

. . The reqd points are (4,11), (-4,-31/3)

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