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15.42 degrees

Q: A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height What is the angle of projection?

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45 degrees.

when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,

horizontal projectile means to project horizontaly from any height h and it forms equation of parabola if we throw any object it goes horizontal and after this it goes down and by the equation s=ut+1/2at*twe can find following things from it # time ofprojectile # distance travelled #effect of gravity

"the higher the altitude the lower the range "

Max height H = u2 sin2@ / 2g So as we increase the angle of projection, then max height too increases and its value will be just u2/2g when it is projected vertically upwards ie @ = 90 deg

Related questions

45 degrees.

The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.

projection speed projection angle projection height

At the maximum height of projectile motion, the vertical component of velocity is zero while the horizontal component of velocity remains constant. Therefore, the total velocity of the projectile at the maximum height is equal to the magnitude of its horizontal component of velocity.

The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.

The maximum height of a projectile depends on its initial velocity and launch angle. In ideal conditions, the maximum height occurs when the launch angle is 45 degrees, reaching a height equal to half the maximum range of the projectile.

To find the projectile motion of an object, you can use the equations of motion for horizontal and vertical components. The horizontal motion is constant, while the vertical motion is affected by gravity. By determining the initial velocity, angle of projection, and acceleration due to gravity, you can calculate various parameters like range, maximum height, and time of flight.

To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.

If a projectile takes 8 seconds to reach its maximum height, it will take another 8 seconds to return to its original elevation. Presuming it is lauched from flat ground and returns to the ground, its total time in flight would be 16 seconds. If it is launched from a hill, or at a hill, more information would be needed.

The velocity of a projectile at its maximum height is zero. This is because at the highest point of the projectile's trajectory, all of its initial kinetic energy has been converted into potential energy, causing the velocity to momentarily become zero.

The two components of a projectile are the horizontal component, which determines the distance the projectile travels, and the vertical component, which influences the projectile's height and the time it takes to reach the highest point and return to the ground.

The horizontal component of velocity remains constant throughout the projectile's motion, as there are no horizontal forces acting on the projectile to change its speed. This means that the projectile will travel the same horizontal distance over equal time intervals, forming a parabolic trajectory.