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A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height What is the angle of projection?
15.42 degrees
How can you used trigonometry in projectile motions?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
What is a horizontal projectile?
horizontal projectile means to project horizontaly from any height h and it forms equation of parabola if we throw any object it goes horizontal and after this it goes down and by the equation s=ut+1/2at*twe can find following things from it # time ofprojectile # distance travelled #effect of gravity
Explain the effect of changing the angle of projection on the magnitude of maximum height?
"the higher the altitude the lower the range "
What is the Effect of changing the angle of projection on the magnitude of maximum height?
Max height H = u2 sin2@ / 2g So as we increase the angle of projection, then max height too increases and its value will be just u2/2g when it is projected vertically upwards ie @ = 90 deg
A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height What is the angle of projection?
15.42 degrees
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
What is the factor influence the distance and time in projectile motion?
projection speed projection angle projection height
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
How high does projectile go?
The maximum height of a projectile depends on its initial velocity and launch angle. In ideal conditions, the maximum height occurs when the launch angle is 45 degrees, reaching a height equal to half the maximum range of the projectile.
How do you find projectile motion?
Projectile motion is a form of motion in which a projectile is thrown near the earth's surface. When thrown, the projectile moves along a curved path because of gravity. An example of projectile motion is a sprinkler shooting water into the air and the water falling back down to Earth.
How can one determine the maximum height reached by a projectile?
To determine the maximum height reached by a projectile, you can use the formula: maximum height (initial vertical velocity)2 / (2 acceleration due to gravity). This formula calculates the height based on the initial vertical velocity of the projectile and the acceleration due to gravity.
How can you throw a projectile so that it has zero speed at the top?
To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.
How can one determine the maximum height reached in projectile motion?
To determine the maximum height reached in projectile motion, you can use the formula: textMaximum height left(fracv02 sin2(theta)2gright) where ( v0 ) is the initial velocity, ( theta ) is the launch angle, and ( g ) is the acceleration due to gravity. By plugging in these values, you can calculate the maximum height the projectile reaches.
In the oblique projection a projectile reaches the maximum height in 8 seconds it is time of flight is?
If a projectile takes 8 seconds to reach its maximum height, it will take another 8 seconds to return to its original elevation. Presuming it is lauched from flat ground and returns to the ground, its total time in flight would be 16 seconds. If it is launched from a hill, or at a hill, more information would be needed.
What happens to the velocity of a projectile at its maximum height?
The velocity of a projectile at its maximum height is zero. This is because at the highest point of the projectile's trajectory, all of its initial kinetic energy has been converted into potential energy, causing the velocity to momentarily become zero.
