Naderqawasmi4183
Acceleration cannot be measured in metres per second. There is, therefore a fundamental problem with the question.
Wiki User
∙ 10y agoAt the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
2 meters every second. bit pointless
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
The average speed = 1/2 (initial speed + final speed) = 1/2 (15 + 25) = 1/2 (40) = 20 meters per second.The distance traveled = (average speed) x (time) = (20 x 7) = 140 meters.
5.0 meters every second.
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.
The distance traveled by the car can be calculated using the equation (s = \frac{1}{2}at^2), where (s) is the distance, (a) is the acceleration, and (t) is the time. Plugging in the values, we have (s = \frac{1}{2} \times 10 \times (4)^2 = 80) meters. Therefore, the car will travel 80 meters in 4 seconds.
2 meters every second. bit pointless
1249 + 2987 + 66245 = 70481
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
The average speed = 1/2 (initial speed + final speed) = 1/2 (15 + 25) = 1/2 (40) = 20 meters per second.The distance traveled = (average speed) x (time) = (20 x 7) = 140 meters.
60.912 meters in that time
5.0 meters every second.
gravity
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.
23.6 meters per second.