The area before would be 13.5 in2. When the length and width are doubled, the new length is 9 inches and the new width is 6 inches, giving the new rectangle an area of 54 in2. Subtract 13.5 from 54, giving you 40.5, which is the difference and the change of the area.
Work
A=lw
A=(4.5 in)(3 in)
A=13.5 in2
A=lw
A=(9 in)(6 in)
A=54 in2
The dimensions of the rectangle are 3 inches by 14 inches
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
(15 x 20) sq inches.
4 x 10
You have given 3 dimensions and not the shape. For area you generally need two dimensions, like for a rectangle. The area of this is Length by width.
The dimensions of the rectangle are 3 inches by 14 inches
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
Missing information. The rectangle could be a square then the two sides would be the square root of 5000 or about 70.71. As the rectangle gets longer the sides change and thus the dimensions.
12 square feet.
Without the dimensions, we won't be able to tell. The area of a rectangle is the length times the width. If those dimensions are in inches, the area will be in square inches.
26.4 inches for the diagonal.
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula
The area of Joseph’s rectangular homework desk is 1,008 square inches. If the length of his desk is 42 inches, how wide is his desk?
157.6102789 inches
(15 x 20) sq inches.
4 x 10
Its dimensions are 6 inches by 7 inches because 2(6+7)=26 inches and 6*7=42 square inches